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(F)=-3F^2-7F-2
We move all terms to the left:
(F)-(-3F^2-7F-2)=0
We get rid of parentheses
3F^2+7F+F+2=0
We add all the numbers together, and all the variables
3F^2+8F+2=0
a = 3; b = 8; c = +2;
Δ = b2-4ac
Δ = 82-4·3·2
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{10}}{2*3}=\frac{-8-2\sqrt{10}}{6} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{10}}{2*3}=\frac{-8+2\sqrt{10}}{6} $
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